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2nd Year Mathematics Chapter 6 Test2nd Year · Mathematics · Federal (FBISE)
Q1. Multiple choice questions (Attempt all · 10 × 1 = 10)
- The point of intersection of right bisectors of a triangle is called:
- If the determinant of three points is zero then the points are:
- The lines represented by ax²+ 2hxy + by²= 0 are imaginary if:
- The point of intersection of three medians of a triangle is called:
- The lines represented by ax²+ 2hxy + by²= 0 are coincident if:
- Half the determinant of vertices of a triangle gives its:
- If the determinant of coefficients of the three lines is 0, then the lines are:
- The lines represented by ax²+ 2hxy + by² are real and distinct if:
- Equation ax + by + c = 0 passes through origin if:
- Which of the following is perpendicular to ?
Q2. Short questions (Attempt any 6 of 8 · 6 × 2 = 12)
- Find the lines represented by each of the following joint equation: 7x²− 2xy − 9y²= 0
- Find the lines represented by each of the following joint equation. 5x²+ 3xy − 2y²= 0
- Find the lines represented by each of the following joint equation: x²+ 6xy = 0
- Find the area of triangle bounded by the lines. 4x − 5y + 7 = 0, x − 2 = 0 and y + 1 = 0
- Find the area of triangle if points (4 , - 2) , (- 2 , 4) and (5 , 5) are vertices of a triangle.
- Using the formula of area, find x if the points P(3, 2), Q(−1, −1), R(7, 3) are collinear.
- Find the lines represented by each of the following joint equation. x²− 3xy − y²= 0
- Find the area of triangle bounded by the lines. x − 2y − 6 = 0, 3x − y + 3 = 0 and 2x + y − 4 = 0
Q3. Long questions (Attempt any 2 of 3 · 2 × 4 = 8)
- Find circumcenter of a triangle ABC with A(0 , 0) , B(6 , 0) and C(0 , 6). Also prove that circumcenter, centroid and orthocenter are collinear.
- A landscaper is designing a triangular garden bed with vertices A(1, 4), B(5, 1) and C(8, 6). Calculate the cost of planting mango trees in the garden @ Rs. 70 per sq. unit.
- Find a joint equation of straight lines through the origin and perpendicular to the lines represented by 3x² + 5xy + 2y² = 0